Battleyachts
Once you finally get a hit though…it’s game over.
I put all my ships in one little cluster, I play people infrequently that they forget I do that. It’s a pretty good strategy
Don’t worry I’ve got backups
The backups:
I remember playing battleship with one of my cousins while at our grandma’s for christmas and I kept winning because they never looked up and noticed the mirror on the ceiling. 😈
…why is there a mirror on the ceiling?
Were you playing on grandmas bed?Their dining room had a mirrored ceiling. I think their house was from the 70s or some shit.
Was there any pink champagne on ice by any chance?
And a lot of pineapples in the decor?
The real battleship cheat was marking the opponents shots as well as your own and moving ships accordingly. I mean, it’s not like real ships don’t move.
Don’t you always mark the opponent’s shots?
They didn’t come with enough markers originally to do that. The only way i was able to as a kid was because we had the peices from a second game set.
It’s always had way more miss markers than we ever needed. And it was in the mid 80s
I suppose strictly speaking you only need to mark the hits. If you’re not cheating, your opponent’s misses don’t really matter much.
I must be not that bright because I played many games of battleship in my childhood and never even considered the possibility.
You’re not allowed to reposition after the game starts
Maybe you aren’t. ITT we cheatin’.
Please. We are simply introducing an element of realism.
Battleships 2 Electric Bogaloo
That has zero strategic advantage. it only hurts your odds of winning.
*Edit: Since this has gotten a fair amount of debate, let me end it for the couple of youl who think I’m incorrect.
When played normally, the odds of finding the 5 spot ship are much higher than finding the 2 spot ship (duh).
You have essentially made a single 5 spot ship by stacking.
When your opponent lands a hit, they are required to state what ship was struck. This means that once there’s a hit made on those ships, you have to name off ALL the ships under the peg.
You transformed a game where you had to find a 5 peg ship, 4 peg, 3 peg, and a 2 peg ship into a game where all you have to do is find the easiest ship to locate (5 peg) and you win the game.
This is a no brainer.
Also, just for the record, it is against the rules to stack ships.
The grid is 10x10, so 100 spaces. Placed legally, your five ships take up 17 spaces. That means if your opponent picks a space at random, there is a 17% chance they will get a hit.
It you cheat like this, your five ships only take up 5 spaces. That means if your opponent picks a space at random, there is a 5% chance they will get a hit.
So, purely based on chance, this increases the odds of your opponent not beating you. You just have to make sure to also be on the offensive and sink all their battleships quickly, because if they happen to hit your battlestack just once, that means they are going to sink it all within the next 4-7 turns.
What you calculated are not the chances of the opponent not beating you, you calculated the chance of getting the first hit. But it is the last ship being hit that will make you lose.
Imagine player A using a regular strategy, and B using this stacking strategy. Now imagine that B gets insanely lucky and sinks all of A’s ships except their largest one, without missing any at all (while A keeps missing all their shots). So now, even after all that insane luck from player B, who has a better chance of winning? At this point, they both have only 5 spaces which can be hit, and any hit will quickly end the game, so they both have 50% chance to win right?
This means that clearly if B doesn’t get insanely lucky in the first turns of the game, then A will have much better chances to win. A’s chance to win reduces to it’s absolute minimum at 50% when it has only one single 5-length ship left.
If you had a ship on every possible space, they would have a 100% chance of landing a hit, so by your logic this would be worse. But it would take 100 turns to sink you, which is the best possible outcome.
Having only one 5 space ship is objectively worse than having one five space ship and all the others. Unless of course you also created a new rule that they have to hit the same spot multiple times, once for each ship.
At that point you’re just playing Calvin Ball, though, and you might as well put the ships under your chair and claim “You never said floor!”
If you had a ship on every possible space, they would have a 100% chance of landing a hit, so by your logic this would be worse.
Yeah, because the challenge in Battleship is primarily the locating of the battleships. Having a 100% chance of being hit would indeed be bad.
Lol. I’m starting to wonder if you ever really played Battleship. You sound like you’d be terrible at the game.
How so? Am I wrong?
On a very fundamental and obvious level. It’s why you have all those down votes.
When the smallest ship (can’t remember what its called) is destroyed, you would then tell your opponent that they sunk it. It would be unlikely that they would continue to strike the next space in that row/column.
According to the rules (which also state you can’t stack ships. Lol) you’re supposed to state which ship was hit.
This means that you would have to say the names of all the ships that just got hit. Also, if you were trying to skirt that rule by not saying the names of all the ships underneath, and only saying the name of the top ship, the odds that both if your opponents first guesses that struck would hit the 2 spot ship are pretty low.
Does 1 hit cause damage to all the ships in the stack that occupy the hit space? Or does only the top-most ship take the damage such that the top ships shield the bottom ones?
By marking design only allowing one peg to mark places you’ve called out, it would strongly be implied that it would only make sense for the hit to happen on all the ships under the spot.
Depends on how hard you want to cheat/ragebait your opponent
I’ll add to this, it’s not just about finding the initial probability since the probability for event B given A, or event C given A and B, these would increase the liklihood of being found. I couldn’t tell you exactly what the probability is but say for example event B given A, it would be 1/n for n being the number of legal spaces around A. So if the ship was in the middle of the board it would have the smallest probability of being found but if you’re along a wall, there’s only 3 possible legal spaces so the probability increases to 33.3℅, and if A was sandwitched between two walls, the probability of B is 50℅.
so if there’s a moral to this story, assert dominance and put all your pieces in the center.
False, they hit two and they think they’ve already sunk the ship
Double false. That implies that they happen to luck out and hit the 2 peg ship first with both guesses, when the odds are that at least one of their guesses would likely hit one of the other 3 spots with ships on it.
By the rules, you also have to state what ship is hit and state when a ship has been sunk.
Most iterations of the game assume you cannot place ships right next to each other. So, when you down a ship in a normal configuration, you immediately know the surroundings are free of ships.
In this placement, all but these 4 cells will not give you such an advantage. Therefore, the tactic is advantageous as it keeps the opponent with less intel.
Correction: digging deeper, it seems like many people know Battleship by the Hasbro/Milton Bradley edition, which doesn’t have this rule. But the game itself is much older, and many of its editions do include the rule. At the very least, this rule is highly popular in Russia, Germany and Spain.
That isn’t a rule at all, dude. You must had had a house rule when you were a kid.
It is in the rules that you can’t stack ships tho. Lol
Certainly not just a house rule, I’ve met it everywhere.
And, as it seems from further down the thread, it seems to be the difference because large parts of the world rely on Hasbro’s Battleship as the rule source, while the other seems to play by older rules (by the time Hasbro/Milton Bradley released the game, it was already almost a century old).
Others from Spain and Germany also seem to know that rule, but it was not in the official Hasbro version of the game. This is what appears to make that difference.
Lol at trying to cop out on being wrong by claiming you were basing your answer on the pre 1963 pencil and paper game of Battleship. What’s worse is that you COULDN’T stack ships in the paper version and that the picture\meme for this post is using the boardgame.
You’re a riot, man. People must love how right you always say you are.
You’re either serious about it and trying to turn a friendly game meme discussion into some kind of battle, or you’re trolling and doing so with 0 finesse. Keep your game a little higher.
Either way, since you love being contested, here are pre-1963 ship figures for Battleship, dated early XX century:
Hasbro hasn’t been first in that, either. They are just large enough to dictate what is considered to be “official”. And this is far from isolated case.
Lol. Yeah. That’s what you were basing your rules on. Sure.
Most iterations of the game assume you cannot place ships right next to each other.
I have never heard that rule. I cannot see that anywhere, even as a variation
Huh, I dug down and apparently it’s a regional quirk?
Even the Wikipedia article about the game doesn’t mention it in English, but does mention it in Russian.
English:
Before play begins, each player secretly arranges their ships on their primary grid. Each ship occupies a number of consecutive squares on the grid, arranged either horizontally or vertically. The number of squares for each ship is determined by the type of ship. The ships cannot overlap (i.e., only one ship can occupy any given square in the grid) or be placed diagonally.
Russian (translated by yours truly):
The playing field is typically a 10x10 square, on which the fleet is placed. <…> When placed, ships should not touch each other by sides or corners. Some variations may lack this rule.
Also, apparently it is common for the game to have 5-long ships, which don’t appear in the Russian versions.
This is also the case for the German version I player, funny.
How odd that they would bother changing the rules regionally.
I think it’s for Russian knock off version of Battleship and not the real version. Especially with the talk about all 5 ships being carrier sized 5 peg ships.
The game is actually over a century old - at least in Russia, it first appeared at the edge of XIX and XX centuries. In the US, Starex started making notebooks for the game in 1931.
The Milton Bradley/Hasbro Battleship, which seems to be the most recognizable internationally as the Battleship game, appeared only in 1967. So, it is a knock-off of a knock-off, actually, made almost a century after the original.
We also don’t typically use a board, we just use a white checkered sheet of paper, which seems to be one of the classic versions of the game. But ship figures for the game did exist as long back as the early XX century.
Blagh blagh blagh. No one gives a shit it started with pencil and paper. It’s been a board game for like 60 years and the picture in this post is of the board game. LL
We have the same rule in Spain
Art of the deal
hold on there, it actually does have strategic advantage from a statistical perspective.
the basic notion is that for a probability of event A to occur it is proportional to the area of the event; so if larger area, larger probability, smaller area, smaller probability.
if we take that idea and apply the same basis to battleship you could say the probability as the sum of each probability of each point which is 0℅ if we span the area to infinity.
practically speaking, this is not true as you can’t span to an infinite scale, but you could say that the probability of hitting a point is 1℅ since battleship is a 10 x 10 grid so the probability is just 1/(10 * 10) = 0.01. Then the probability gets more complicated since you are being asked what is the probability of the second, third, fourth, etc… point being hit given that initial probability. the probability grows dependent on the first point being hit.
I’m sure there is a way to find algorithmically an optimal method to finding in what location are the best positions in battleship, but generally speaking, no, there are worse conditions that have a higher probability of being guessed
You must write statistics for Fox News.
There’s a lower chance of getting hit on turn 1, but it takes more turns to sink a five space ship and all of the others than just one five space ship. The goal is to last more turns with at least one boat, not avoid getting hit for the longest. I don’t see the advantage.
Unless you add an extra rule requiring you to shoot the same space multiple times.
Wasn’t the same picture posted yesterday?
High risk, high reward.
I am not seeing it. In this community?
EDIT: Oh, it’s a user I have blocked. No wonder I didn’t see that before posting this.
The one from yesterday was slop. This one at least some effort behind it (not much - it’s still a shitpost).
Better a low effort shitpost made by a human than zero effort algorithmic slop.
I’ll pay top dollar for a stained, crumpled napkin doodle of the thing I’m interested in before I spend a cent on slop.
Good artists copy, great artists steal.
-Me
OpenAI friend request incoming
“Stealing” from the slop-scammers can never be stealing.
Welcome to the internet, please enjoy your stay.
We’ve got mountains of content, some better, some worse
If none of it’s of interest to you, you’d be the first
It was a different picture, but exactly same meme - I don’t know why people do shit like that
Maybe yesterdays post was a slopified AI version, and today is the original photo.
The best part is, this dumb cheater has strictly reduced their odds of victory. This is bait.
Ah yes the straddle-ship strat
That’s high visibility, can be seen over the top of the board.
